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30 June, 19:28

How do you solve 3log_3 4a=3?

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  1. 30 June, 20:40
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    3 log₃ 4a=3

    1) a (log_b c) = log_b c^a

    log₃ (4a) ³=3

    2) log_a x=n ⇔ a^n=x

    log₃ (4a) ³=3 ⇔ 3³ = (4a) ³

    27=64a³

    a³=27/64

    a=∛ (27/64)

    a=3/4

    Answer: a=3/4
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