How do you find the domain and range of f (x) = 8x^2-5x 2?

The domain of f (x) = 8x^2 - 5x + 2 is all real numbers.

For the range, f (x) = 8x^2 - 5x + 2 written in vertex form is f (x) = 8 (x^2 - 5/8x + 1/4) = 8 (x^2 - 5/8 + 25/256 + 1/4 - 25/256) = 8 (x - 5/16) ^2 + 8 (39/256) = 8 (x - 5/16) ^2 + 39/32

The range is all real numbers greater than or equal to 39/32