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30 March, 19:51

How can 1/5x-2=1/3x+8 be set up as a system of equation

5y-5x=-10; 3y-3x=24

5y-5x=-10; 3y-3x=24

5y-x = - 10; 3y+x=24

5y-x=-10; 3y-x=24

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Answers (1)
  1. 30 March, 21:31
    0
    Hello:

    1/5x-2=1/3x+8

    let; y = 1/5x-2 ... (1)

    y=1/3x+8 ... (2)

    by (1) : 1/5 x = y+2

    x = 5y + 10 ... (*)

    by (2) : 1/3x = y-8

    x = 3y-24 ... (**)

    (*) : 5y-x = - 10

    (**) : 3y-x = 24 ... (last answer)
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