The equation of a circle is (x-3) ^2 + (y+8) ^2=36. Relative to the standard equation of a circle (x^2+y^2=r^2), how has this circle been shifted? What is the radius of the circle?
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Home » Mathematics » The equation of a circle is (x-3) ^2 + (y+8) ^2=36. Relative to the standard equation of a circle (x^2+y^2=r^2), how has this circle been shifted? What is the radius of the circle?