inverse of 2 (x - 2) 2 = 8 (7 + y)

a) - 2 (x - 2) 2 = - 8 (7 + y)

b) 1/4x^2-x-6

c) - 2 + / - sqrt 28+4x

d) 2 + / - sqrt 28+4x

2 (x - 2) ² = 8 (y + 7)

2 (x - 2) (x - 2) = 8 (y) + 8 (7)

2[x (x - 2) - 2 (x - 2) ] = 8y + 56

2[x (x) - x (2) - 2 (x) + 2 (2) ] = 8y + 56

2 (x² - 2x - 2x + 4) = 8y + 56

2 (x² - 4x + 4) = 8y + 56

2 (x²) - 2 (4x) + 2 (4) = 8y + 56

2x² - 8x + 8 = 8y + 56

- 56 - 56

2x² - 8x - 48 = 8y

8 8

¹/₄x² - x - 6 = y

¹/₄y² - y - 6 = x

+ 6 + 6

¹/₄y² - y = x + 6

4 (¹/₄y² - y) = 4 (x + 6)

4 (¹/₄y²) - 4 (y) = 4 (x) + 4 (6)

y² - 4y = 4x + 24

y² - 4y + 4 = 4x + 24 + 4

y² - 2y - 2y + 4 = 4x + 28

y (y) - y (2) - 2 (y) + 2 (2) = 4x + 28

y (y - 2) - 2 (y - 2) = 4x + 28

(y - 2) (y - 2) = 4x + 28

(y - 2) ² = 4x + 28

√ (y - 2) ² = √ (4x + 28)

y - 2 = √4 (x) + 4 (7)

y - 2 = √4 (x + 7)

y - 2 = 2√ (x + 7)

+ 2 + 2

y = 2 ± 2√ (x + 7)

The answer is D.