George's page contains twice as many type words as Bill's paid and Bill's page contains 50 fewer words and Charlie's page. If each person can type 60 words per minute, after one minute, the difference between twice the number of words on bills page and the number of words on Charlie's paid 210. How many words did bills page contain initially?

For this, we use simultaneous equations. Let George's page be g, Charlie's be c and Bill's page be b.

First, George's page contains twice as many type words as Bill's.

Thus, g = 2b.

Second, Bill's page contains 50 fewer words than Charlie's page.

Thus, b = c - 50.

If each person can type 60 words per minute, after one minute (i. e. when 60 more words have been typed) the difference between twice the number of words on bills page and the number of words on Charlie's page is 210.

We can express that as 2b - c = 210.

Now we need to find b, since it represents Bill's page.

We can substitute b for (c - 50) since b = c - 50, into the equation 2b - c = 210. This makes it 2 (c - 50) - c = 210.

We can expand this to 2c - 100 - c = 210.

We can simplify this to c - 100 = 210.

Add 100 to both sides.

c - 100 + 100 = 210 + 100

Then simplify: c = 210 + 100 = 310.

Now that we know c, we can use the first equation to find b.

b = c - 50 = 310 - 50 = 260.

260 is your answer. I don't know where George comes into it. Maybe it's a red herring!