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13 December, 22:55

An engineer is surveying a building with a device that is 6 feet above the ground. he is 60 feet from the building and is looking with an angle of elevation of 45°. how tall is the building? ... i'm really bad at trig. x ... x

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  1. 14 December, 01:52
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    The entire system forms a right angle triangle.

    Let the height of the bulding be x, then tan 45 = (x - 6) / 60

    60 = x - 6

    x = 60 + 6 = 66

    Therefore the height of the building is 66 feet.
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