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14 December, 23:08

Solve: 20x-18<50<36x-16

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  1. 15 December, 02:27
    0
    So this is actually composed o 2 sentances

    20x-18<50 AND 50<36x-16

    so solve each and find solutions where x is the same in both sentances

    20x-18<50

    add 18 to both sides

    20x<68

    divide both sides by 20

    x<3 and 2/5

    then the second sentance

    50<36x-16

    add 16 to both sides

    66<36x

    divide both sides by 36

    1 and 5/6
    so

    since it is and, combine

    3 and 2/5>x>1 and 5/6 or

    17/5>x>11/6

    the solution is

    S=x
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