Act as if parentheses were absolute value lines.

(3x+6) - 2>10

How do I find the answer and what is it.

Let's actually write this inequality with the absolute value operator:

|3x+6|-2>10. The symbol " | " is to be found at the extreme right of the main keyboard; it's the character you get if you type "capital /."

I'd simplify the problem first: Add 2 to both sides of the inequality.

This results in |3x+6|=8.

Next, I'd factor 3 out of the two terms within the absolute value symbol:

3|x+2|=8, or |x+2|=8/3

One way of solving this is as follows: Create 2 equations from |x+2|>8/3. One would be + (x+2) = 8/3; the other would be - (x+2) >8/3.

Can you solve these two new inequalities for x? Your answer to this problem must contain two inequalities for x values.

Another approach would be to regard x = - 2 as the center of a circle of radius 8/3. x would have to be smaller than [-2-8/3] or greater than [-2+8/3]. In words, the distance of x from the center (x=-2) must be greater than 8/3 in either case (remembering that "distance" is always positive).

|3x+6|>12

3x+6> 12

x>2

- (3x+6) > 12

-3x-6>12

-3x>18

x<6

Therefore x>2 or x<6