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7 February, 03:05

Find the standard form of the equation of the parabola with a focus at (0, 6) and a directrix at y = - 6.

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  1. 7 February, 06:39
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    From the given information, the parabola is a regular parabola facing up with vertex at the origin.

    Required equation is (x - 0) ^2 = 4p (y - 0)

    But 0 + p = 6 = > p = 6

    Therefore, required equation is x^2 = 4 (6) y

    x^2 = 24y

    y = 1/24 x^2
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