A bag has 4 red marbles, 12 blue marbles and 6 yellow marbles. What is the probability of picking a yellow marble, replacing it, and then picking a blue marble?

a) 1/18

b) 18/121

c) 15/22

d) 22/131

Question

Mathematics

Caitlyn Powers

10 April, 01:06

A bag has 4 red marbles, 12 blue marbles and 6 yellow marbles. What is the probability of picking a yellow marble, replacing it, and then picking a blue marble?

a) 1/18

b) 18/121

c) 15/22

d) 22/131

+1

Answers (1)

Know the Answer?

Dereon Mcmillan · Answer 1

Probability of picking a yellow marble = no of yellow marbles/total number of mables = 6 / (4 + 12 + 6) = 6/22 = 3/11

Probability of picking a blue marble = 12/22 = 6/11

Probability of picking a yellow marble and a blue marble = 3/11 x 6/11 = 18/121

A bag has 4 red marbles, 12 blue marbles and 6 yellow marbles. What is the probability of picking a yellow marble, replacing it, and then picking a blue marble?a) 1/18b) 18/121c) 15/22d) 22/131

A bag has 4 red marbles, 12 blue marbles and 6 yellow marbles. What is the probability of picking a yellow marble, replacing it, and then picking a blue marble?

a) 1/18

b) 18/121

c) 15/22

d) 22/131