A ball is thrown into the air from a height of 9cm above the ground, and its height is given by S=128+32t-16t^2, where t is the time in seconds

1) find the values of t that makes S=0.

2) Do both of the values of t have meaning for this application? Explain why

-16t² + 32t + 128 = 0

-16t² + 64t - 32t + 128 = 0

-16t (t - 4) - 32 (t - 4)

(-16t - 32) (t - 4) = 0

-16t - 32 = 0 t - 4 = 0

-16t = 32 t = 4

t = - 2

t = - 2 and t = 4 are the values that makes S = 0.

Yes, because if you apply either of these values alone, S will be 0.