Find three consecutive positive integers such that the square of the first is equal to the Third

3 consecutive positive integers : x, x + 1, x + 2

x^2 = x + 2

x^2 - x - 2 = 0

(x + 1) (x - 2) = 0

x + 1 = 0

x = - 1 ... this is an extraneous solution that does not work

x - 2 = 0

x = 2

check ...

square of the first = third

x^2 = x + 2

2^2 = 2 + 2

4 = 4 (correct)

so ur 3 integers are 2,3, and 4