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15 October, 06:37

The sum of three numbers is 79. The second number is 5 times the first, while the third is 16 more than the first. Find the number

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  1. 15 October, 06:46
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    Let the 1st number be x; 2nd number be y; 3rd number be z.

    x + y + z = 79

    x = number we are looking for.

    y = x * 5 = = > 5 times the first

    z = x + 16 = = > 16 more than the first

    Therefor,

    x + (x * 5) + (x+16) = 79

    1st step, multiply the 2nd number: x * 5 = 5x

    x + 5x + x + 16 = 79

    Add all like numbers:

    7x + 16 = 79

    To get x, transfer 16 to the other side and change its sign from positive to negative.

    7x = 79 - 16

    7x = 63

    To get x, divide both sides by 7

    7x/7 = 63/7

    x = 9

    To check. Substitute x by 9.

    x + (x * 5) + (x+16) = 79

    9 + (9 * 5) + (9 + 16) = 79

    9 + 45 + 25 = 79

    79 = 79 equal. value of x is correct.
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