What is the center and radius of the following circle: x^2 + (y - 6) ^2 = 50

What is the center and radius of the following circle: x^2 + (y _ 6) ^2 = 50,

circle quation formula is (x-a) ^2 + (y-b) ^2 = R², so by identifying each term, we find (x-a) ^2=x^2 = (x-0) ^2, (y-b) ^2 = (y _ 6) ^2, R² = 50, implies R = 5sqrt (2),

it is easy to identify that the center is (a, b) = (0, 6)

the radius is R = 5sqrt (2),

Center: (0, 6)

radius = sqrt (50) = 5sqrt (2)