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16 January, 04:24

What is the center and radius of the following circle: x^2 + (y - 6) ^2 = 50

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  1. 16 January, 06:31
    0
    What is the center and radius of the following circle: x^2 + (y _ 6) ^2 = 50,

    circle quation formula is (x-a) ^2 + (y-b) ^2 = R², so by identifying each term, we find (x-a) ^2=x^2 = (x-0) ^2, (y-b) ^2 = (y _ 6) ^2, R² = 50, implies R = 5sqrt (2),

    it is easy to identify that the center is (a, b) = (0, 6)

    the radius is R = 5sqrt (2),
  2. 16 January, 07:07
    0
    Center: (0, 6)

    radius = sqrt (50) = 5sqrt (2)
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