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24 April, 19:55

2 - (4p+3) = - 3 (p+2) - (2p+3)

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Answers (2)
  1. 24 April, 22:07
    0
    Simplifying

    2 + - 1 (4p + 3) = - 3 (p + 2) + - 1 (2p + 3)

    Reorder the terms:

    2 + - 1 (3 + 4p) = - 3 (p + 2) + - 1 (2p + 3)

    2 + (3 * - 1 + 4p * - 1) = - 3 (p + 2) + - 1 (2p + 3)

    2 + (-3 + - 4p) = - 3 (p + 2) + - 1 (2p + 3)

    Combine like terms: 2 + - 3 = - 1

    -1 + - 4p = - 3 (p + 2) + - 1 (2p + 3)

    Reorder the terms:

    -1 + - 4p = - 3 (2 + p) + - 1 (2p + 3)

    -1 + - 4p = (2 * - 3 + p * - 3) + - 1 (2p + 3)

    -1 + - 4p = (-6 + - 3p) + - 1 (2p + 3)

    Reorder the terms:

    -1 + - 4p = - 6 + - 3p + - 1 (3 + 2p)

    -1 + - 4p = - 6 + - 3p + (3 * - 1 + 2p * - 1)

    -1 + - 4p = - 6 + - 3p + (-3 + - 2p)

    Reorder the terms:

    -1 + - 4p = - 6 + - 3 + - 3p + - 2p

    Combine like terms: - 6 + - 3 = - 9

    -1 + - 4p = - 9 + - 3p + - 2p

    Combine like terms: - 3p + - 2p = - 5p

    -1 + - 4p = - 9 + - 5p

    Solving

    -1 + - 4p = - 9 + - 5p

    Move all terms containing p to the left, all other terms to the right.

    Add '5p' to each side of the equation.

    -1 + - 4p + 5p = - 9 + - 5p + 5p

    Combine like terms: - 4p + 5p = 1p

    -1 + 1p = - 9 + - 5p + 5p

    Combine like terms: - 5p + 5p = 0

    -1 + 1p = - 9 + 0

    -1 + 1p = - 9

    Add '1' to each side of the equation.

    -1 + 1 + 1p = - 9 + 1

    Combine like terms: - 1 + 1 = 0

    0 + 1p = - 9 + 1

    1p = - 9 + 1

    Combine like terms: - 9 + 1 = - 8

    1p = - 8

    Divide each side by '1'.

    p = - 8

    Simplifying

    p = - 8
  2. 24 April, 22:47
    0
    Ultimately, you want the variable p on one side of the equals sign, and the value of p on the other.

    First, get rid of the parenthesis by distributing.

    There is an invisible - 1 in front of the first and last set of parenthesis, and a one times any number is the number itself, so you are essentially distributing the negative sign.

    So you have: 2-4p-3 = - 3p-6-2p-3

    Next, Combine like terms.

    Can you take it from there?
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