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26 October, 04:51

Triangle ABC has three sides with these lengths: AB = 9, BC = 40, and CA = 41. What is the value of cos C? A. 9/41 B. 40/9 C. 40/41 D. 9/40

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  1. 26 October, 07:51
    0
    The answer is letter C which is 40/41. If you draw a triangle the sides found in the cos C is BC which is equal to 40 and the CA which is equal to 41 or the 40/41. It can not be the AB since it is in the opposite side of the cos C.
  2. 26 October, 08:39
    0
    It's a rectangular triangle because:

    9² + 40² = 41²

    81 + 1600 = 1681

    1681 = 1681

    Answer: C. cos∡C = 40/41
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Home » Mathematics » Triangle ABC has three sides with these lengths: AB = 9, BC = 40, and CA = 41. What is the value of cos C? A. 9/41 B. 40/9 C. 40/41 D. 9/40
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