What is the probability of being dealt 3 tens and 2 kings from a deck of cards?

We need to find the probability of getting 3 tens and 2 kings

First we find possible combinations of selecting 5 cards from 52 cards

That is 52C5

We use formula n! / r! (n-r) !

52! / 5! (52-5) ! = 2598960

In 52 cards, we have 4 tens and 4 kings

We need to select 3 tens from 4 tens

So we find 4C3 = 4! / 3! (4-3) ! = 4

We need to select 2 kings from 4 kings

So we find 4C2 = 4! / 2! (4-2) ! = 6

The probability of 3 tens and 2 queens = (4C3 * 4C2) / 52C5

(4*6) / 2598960 = 1/108290