Find 3 consecutive integers such that the smallest is ten less than twice the greatest

Question

Mathematics

Reese Hayden

9 February, 21:13

Find 3 consecutive integers such that the smallest is ten less than twice the greatest

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Answers (1)

Know the Answer?

Jasiah Watts · Answer 1

Let the integers be x, x+1, x+2

Now the smallest is ten less than twice the greatest

So (x+2) 2-10=x

2x+4-10=x

2x-x-6=0

x-6=0

x = 6

The integers then are;

6, 7, 8