A rectangles length is 7 inches greater than its width. If the perimeter of the rectangle is 110 inches, find its length and width.

I think it's w (w+7) = 110

Ythat's wrong, perimiter is 2l+2w or 2 (l+w) or just look below at my explanation

l=w+7

perimiter=2l+2w

perimiter=2 (l+w)

subsitute

2 (w+7+w) = permiter

2w+14+2w=4w+14=permiter

4w+14=110

subtract 14 from both sides

4w=96

divide both sides by 4

w=24

width=24

l=w+7

l=24+7

l=31

legnth=31

width=24

The equation for perimeter is P=2 (l+w)

so, the equation is 110=2 (l+w)

we know that l is 7 inches greater than w

so, l=w+7

now, substitute that for l

110=2 (w+7+w)

110=2 (2w+7)

110=4w+14

96=4w

w=24