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1 February, 20:28

A stadium has 45,000 seats. Seats sell for $30 in Section A, $24 in Section B, and $18 in Section C. The number of seats in Section A equals the total number of seats in Sections B and C. Suppose the stadium takes in $1,168,800 from each sold-out event. How many seats does each section hold?

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  1. 1 February, 21:57
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    A + b + c = 45,000

    30a + 24b + 18c = 1,168,800 reduces to 5a + 4b + 3c = 194,800

    a = b + c

    b + c + b + c = 45,000

    2b + 2c = 45,000

    b + c = 22500 < = = = this is A

    c = 22500 - b

    5a + 4b + 3c = 194,800

    5 (22500) + 4b + 3 (22500 - b) = 194,800

    112500 + 4b + 67500 - 3b = 194,800

    b + 180,000 = 194,800

    b = 194,800 - 180,000

    b = 14,800 <===here is b

    a = b + c

    22500 = 14800 + c

    22500 - 14800 = c

    7700 = c < = = here is c

    so ... A = 22,500, B = 14,800, and C = 7,700
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