A population of 100 frogs increases at an annual rate of 22%. How many frogs will there be in 5 years? Write an expression to represent the equivalent monthly population increase rate.

Exponential growth of the form:

F=Ar^t

F=100 (1.22) ^t

F (5) = 100 (1.22) ^5

F (5) = 270.27

F (5) = 270 to the nearest frog ...

...

1.22=r^12

r=1.22^ (1/12)

F=100 (1.22^ (1/12) ^t)

F=100 (1.22^ (t/12)) now it will produce monthly populations ...

Say we did the same as before but instead of 5 years you have 60 months ...

F (60) = 100 (1.22^ (60/12))

F (60) = 270 to the nearest frog ... : P