Solve the system by substitution 0.3a + 0.1b = 1.3 4/3a + 1/3b = 6

0.3a+0.1b=1.3

4/3a+1/3b=6

First make the second problem into decmoals.

4.3a+.3b=6

Now move the 0.3a to the other side of the equal sign by subtracting

0.1b=1.3-0.3a

Now divide the 0.1 on both sides

b=13-3a

Now substitute the b in the second problem for 13-3a

4.3a+.3 (13-3a) = 6

Multiply the. 3 with 13 and - 3

4.3a+3.9-.9a=6

Subtract the 3.9 on both sides

4.3a-.9a=2.1

Subtract the 4.3a with the. 9a

3.4a=2.1

Now divide 3.4 on both sides

a=.61

Now substitute the a in the first problem for. 61

b=13-3 (.61)

Multiply the - 3 with. 61

b=13-1.83

Now subtract 13 and 1.83

b=11.17

Now your answer is

a=.61

b=11.17