For the system of equations shown below

2x = - y + 6

-4x + 3y = 8

What is the solution to the system of equations?

2x=-y+6

-4x+3y=8

Rewriting the equations;

y+2x=6

3y-4x=8

Multiplying equation I by 3;

3y+6x=18

3y-4x=8

Subtracting equation II from equation I;

10x=10

x=1

Replacing for x in the first equation;

2x=-y+6

2 (1) = - y+6

2=-y+6

2-6=-y

-4=-y

y=4