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12 May, 20:47

For the system of equations shown below

2x = - y + 6

-4x + 3y = 8

What is the solution to the system of equations?

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Answers (1)
  1. 12 May, 21:36
    0
    2x=-y+6

    -4x+3y=8

    Rewriting the equations;

    y+2x=6

    3y-4x=8

    Multiplying equation I by 3;

    3y+6x=18

    3y-4x=8

    Subtracting equation II from equation I;

    10x=10

    x=1

    Replacing for x in the first equation;

    2x=-y+6

    2 (1) = - y+6

    2=-y+6

    2-6=-y

    -4=-y

    y=4
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