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25 April, 05:03

Find the area of an equilateral triangle (regular 3-gon) with the given measurement. 6-inch radius A = sq. in.

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  1. 25 April, 08:32
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    If the radius is the radius of the inscribed circle then the

    side of the triangle = radius * 6 / (sq root (3))

    side = 20.785

    tan 60 = height / half-side

    height = tan 60 * half-side

    height = 1.732 * 10.3925

    height = 17.99981

    triangle area =.5*side*height

    triangle area = 10.3925 * 17.99981

    triangle area = 187.06

    If the radius is the radius of the circumscribed circle then the

    side of the triangle = radius * 3 / (sq root (3))

    side of the triangle = 6 * 3 / sq root (3)

    side of the triangle = 10.3923048454

    half-side = 5.1961524227

    height = tan 60 * half-side

    height = 1.732 * 5.196

    height = 8.9997

    triangle area =.5*side*height

    triangle area = 5.196 * 8.9997

    triangle area = 46.764
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