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15 September, 11:59

How do you do (2 to the - 7) < 2, to the power of negative 7?

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Answers (2)
  1. 15 September, 12:51
    0
    With negative exponents you make it a fraction.

    For example with your equation it would be

    1/2^7<2

    So basically you just flip the fraction to cancel out the negative then you can continue to solve.
  2. 15 September, 13:39
    0
    You would combine like terms, combine 2 too 2 and 2 too - 7 it should be 4 - 14
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