At time t = 0 you have 100 grams of radioactive Chromium-48. Ten hours later you have 74 grams left. What is the half life of Chromium-48?

To calculate what is asked we use the formula for radioactive decay. It is expressed as follows:

An = Ao (e^ (-kt))

We calculate as follows:

An = Ao (e^ (-kt))

74 = 100 (e^ (-k (10)))

k = 0.0301

1/2 = (e^ (-0.0301t))

t = 23 hours

Hope this answers the question.