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3 April, 23:25

What is the y value of the vertex?

y=x^2-10x+24

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Answers (2)
  1. 4 April, 00:51
    0
    x from - 6 to 25, y from - 50 to 10, x^2 - 10x - 24

    vertex = (5,-49)

    x intercept=-2 & 12

    y intercept=-24
  2. 4 April, 02:33
    0
    Hack way

    find x value then plug back

    to find the x value of the vertex in form

    y=ax^2+bx+c

    the x value is - b / (2a)

    so

    y=1x^2-10x+24

    x value is - 10 / (2*1) = - 10/2=5

    sub back

    y=5^2-10 (5) + 24

    y=25-50+24

    y=25+24

    y=49

    y value is 49
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