Find three consecutive natural numbers such that the difference of 5 times the third number and four times the first number is twice the second number

Theya re 1 apart

n, n+1, n+2

difference of 5 times (n+2) and 4 times n is 2 times (n+1)

5 (n+2) - 4n=2 (n+1)

distribute

5n+10-4n=2n+2

n+10=2n+2

minus n both sides

10=n+2

minus 2 both sides

8=n

n+1=9

n+2=10

th enumbers are 8,9,10