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23 September, 08:24

How do you solve x^2-4X-12=0

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  1. 23 September, 11:09
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    x² - 4x - 12 = 0

    Factor the left side: (x + 2) · (x - 6) = 0

    The equation is true if either factor is zero.

    If (x + 2) = 0 then x = - 2.

    If (x - 6) = 0 then x = 6.
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