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10 December, 18:01

Can anyone explain how to differentiate this? (2x^2+3) sin5x

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  1. 10 December, 21:41
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    Hello,

    (u*v) '=u'v+uv'

    u=2x²+3 = = > u'=4x

    v=sin 5x = = >v'=cos 5x * 5

    ((2x²+3 sin (5x)) '=4x * sin (5x) + (2x²+3) * cos (5x) * 5
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