A boy is 24 years younger than his father. In 2 years time the sun of their ages will be 40. Find the present ages of father and son

Let the age of the boy be x.

Therefore the age of the father = x + 24. (The boy is 24 years younger implies that

his father is older by 24 years).

In 2 years time:

The boy will be = (x + 2).

The father will be (x + 24 + 2) = (x + 26).

Sum of their ages = 40.

Therefore (x+2) + (x + 26) = 40.

x + x + 2 + 26 = 40

2x + 28 = 40

2x = 40 - 28

2x = 12.

x = 12/2 = 6. x = 6.

Present ages = x, x + 24. = 6, (6 + 24) = 6, 30.

Boy = 6 years old.

Father = 30 years old.

Cheers.

Ooh fun

x=boy

y=father

x+24=y

(x+2) + (y+2) = 40

subsitute x+24=y into equation

x+2+x+24+2=40

add like terms

2x+28=40

subtract 28 from both sides

2x=40

divide both sides by 2

x=son now=20

father=son+24

father=20+24=44

father=44

son=20