Passes through (3,1), perpendicular to y=-3x+2

As it is perpendicular to y = - 3x + 2 and the gradient of that is - 3 we know that the gradient of our line must be - 1 / - 3 = 1/3.

Now we have the general equation of a line m = (y-y1) / (x-x1) to which we can substitute our values.

1/3 = (y - 1) / (x - 3)

x - 3 = 3 * (y - 1)

x - 3 = 3y - 3

x = 3y