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7 January, 11:09

Find the indicated probability.

Empirical evidence suggests that 25% of Florida drivers are uninsured. If four random Florida drivers are involved in an accident, what is the probability that more than one of them are uninsured?

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  1. 7 January, 12:31
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    The probability that more than one of them are uninsured is the difference between 1 and the probability at one of them is uninsured which is equal to 25%. Thus, to solve for the answer in the question above,

    n = 1 - 0.25

    Thus, the answer is equal to 0.75 or 75%.
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