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27 December, 01:55

Ms smith has 28 sixth graders and 35 seventh graders for math. If she wants to break the two grades into identical groups without any students left over how many students will be I each group?

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  1. 27 December, 03:30
    0
    In this question, there is two class with a different number of students that need to be divided equally. Then you need to determine the number of greatest common factor (GCF) for both numbers. The number factor would be:

    28 = 7 x 2 x 2

    35 = 7 x 5

    The only common factor in both numbers is 7, so making 7 groups will be the answer.
  2. 27 December, 03:48
    0
    Ms Smith has 28 sixth graders and 35 seventh graders

    she wants to break them down into groups with each group having the same number of students from each grade

    for this we have to find the highest common factor of 28 and 35 to see by which both 28 and 35 are divisible by

    factors of 28 and 35 are as follows

    28 - 1,2,4,7,14,28

    35 - 1,5,7,35

    the highest common factor both numbers is 7

    therefore Ms Smith can break them down into 7 groups

    each group will have

    28 / 7 = 4 sixth graders

    35 / 7 = 5 seventh graders

    so each group will have 4 sixth graders and 5 seventh graders

    so in each group there will be 4 + 5 = 9 students

    she will break them down into 7 groups

    each group has 9 students
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