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13 August, 08:31

Two equations are given below:

a - 3b = 16

a = b - 2

What is the solution to the set of problems in the form (a, b) ?

a. (-2, - 6)

b. (-7, - 9)

c. (-11, - 9)

d. (-12, - 10)

+2
Answers (1)
  1. 13 August, 08:47
    0
    You can solve this question by equating the two linear systems (by "substitution" or "elimination")

    By substitution

    -Take Equation 2 and substitute it in Equation 1

    you will have (b-2) - 3b = 16 = > - 2b=18 = > b=-9

    -Then, take b=-9 and substitute it in one of the equations (it doesn't really matter)

    For eg substituting in equation 2 yields a=-11

    Final ans: C where (a, b) is (-11,-9)
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