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20 June, 09:13

What are the zeros of (x) = (3x - 1) (2x + 5) (7x-14) ^2

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  1. 20 June, 09:27
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    I use my calculator (TI-84 Plus CE-T)

    Y1 (the blue one) = (3x-1) (2x+5) (7x-14) ^2

    Graph

    You have 2 zeros

    2nd trace zero

    The first one gives x = 1/3 and y = 0

    (1/3,0)

    The second one gives x = 2 and y = 0

    (2,0)
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