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10 August, 11:45

State the number of positive and negative real roots

x^7-2x^6-19x+20=0

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  1. 10 August, 14:48
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    X⁷ - 2x⁶ + 19x + 20 = 0

    (x⁶ - 1) (x + 20) = 0

    (x³ + 1) (x³ - 1) (x + 20) = 0

    x³ + 1 = 0 x³ - 1 = 0 x + 20 = 0

    - 1 - 1 + 1 + 1 - 20 - 20

    x³ = - 1 x³ = 1 x = - 20

    x = - 1 x = 1
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