Define f (1) in a way that extends f (s) = (s^3-1) / (s^2-1) to be continuous at s=1. Show step-by-step solution.

For a function to be continous right hand limit should be equal to left hand limit

so que means that we have simply find the limit at s tends to 10

f (s) = [ (s-1) (s^2+1s-1) ]/[ (s-1) (s+1 ...

=>f (s) = [s^2+1s+1] / (s+1)

putting s=1

f (s) = 6