What are the solutions to the following system of equations? Select the correct answer below.

y = x2 - 2x + 4

8x + y = 20

a (2, 84) and (-8, 4)

b (-8, 2) and (84, 4)

c (2, 4) and (-8, 84)

d (4, - 8) and (84, 2)

First we take the first equation y=x2 - 2x + 4 and substitute it for the value of y in the second equation ... giving us, 8X + (x^2 - 2x + 4) = 20

8x + x^2 - 2x + 4 = 20

combine like terms x^2 + 6x + 4 = 20

subtract 20 fm both sides x^2 + 6x - 16 = 0

factor (x + 8) (x - 2) = 0

set both factors to = 0 x + 8 = 0 x - 2 = 0

solve x = - 8 and 2

put these amounts into the regular equation to get the value of y

leaving the correct answer as C.

Is it really x2 - 2x because that will not work.