The sum of 4 consecutive integers is 198. What is the fourth number in this sequence.

Let x, x+1, x+2, x + 3 are the numbers

so

x + x + 1 + x + 2 + x + 3 = 198

4x + 6 = 198

4x = 198-6

4x = 192

x = 192/4

x = 48

x + 1 = 48 + 1 = 49

x + 2 = 48 + 2 = 50

x + 3 = 48 + 3 = 51

proof

48 + 49 + 50 + 51 = 198

so the numbers are 48, 49, 50, 51

fourth number in this sequence is 51