Ask Question
28 October, 23:32

Find the derivative of the function ... y = cot2 (sin θ).

+1
Answers (2)
  1. 29 October, 00:18
    0
    Y' = 2 cot (sin t) * derivative of cot (sint t)

    2 cot (sin t) * [ - cosec^2 (sin t) ] * derivative of sin t

    -2 cot (sin t) cosec^2 (sin t) * cos t
  2. 29 October, 00:23
    0
    Y = cot2 (sinФ)

    dy/dФ = d/dФcot2 (sinФ)

    dy/dФ = - cosec²2 (sinФ) d/dФ2 (sinФ)

    dy/dФ = - cosec²2 (sinФ) 2cosФ

    dy/dФ = - 2[cosФ][cosec²2 (sinФ) ]
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Find the derivative of the function ... y = cot2 (sin θ). ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers