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4 May, 19:37

What are the values of x in the following equation:

log (x) (6x+1) - log (x) = 7

There should be 2 values.

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Answers (1)
  1. 4 May, 21:46
    0
    OK. Concentrating only on the first log, here's how it works out:

    log [ x · (6x + 1) ] = log (6x² + x).

    Now looking at the whole left side, it says

    log (6x² + x) - log (x)

    which is log [ (6x² + x) / x ]

    = log (6x + 1).

    So now we have

    log (6x + 1) = 7

    Raise 10 to the

    power of each side: 6x + 1 = 10⁷

    6x = 9,999,999

    x = 9,999,999 / 6

    = 1,666,666.5

    This number works when you plug it into the original equation.

    I'm sorry, but just now, I don't see where a second solution would come from.
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