Let n represent an even integer. Write an expression for the sum of that number and the next three even numbers after it. Simplify your expression fully. ((I just need someone to clarify what I need to do.))

N=an even integer.

the next even number is: (n+2)

the next even number to (n+2) is: (n+2) + 2=n+4

the next even number to (n+4) is : (n+4) + 2=n+6

Therefore, the sumf of thant number and the next even numbers afeter it will be:

n + (n+2) + (n+4) + (n+6)

if we simplifi this expression fully, we have:

n + (n+2) + (n+4) + (n+6) = 4n+12

Answer: Let "n" an even integer, the expression for the sum of tahta number and the next three even numbers after it, will be:

4n+12