Two pools are being filled with water. To start, the first pool contains

1285

liters of water and the second pool contains

1600

liters of water. Water is being added to the first pool at a rate of

32.75

liters per minute. Water is being added to the second pool at a rate of

22.25

liters per minute.

1. After how many minutes will the two pools have the same amount of water?

2. How much water will be in each pool when they have the same amount?

Question

Mathematics

Travis Shepherd

14 April, 13:23

Two pools are being filled with water. To start, the first pool contains

1285

liters of water and the second pool contains

1600

liters of water. Water is being added to the first pool at a rate of

32.75

liters per minute. Water is being added to the second pool at a rate of

22.25

liters per minute.

1. After how many minutes will the two pools have the same amount of water?

2. How much water will be in each pool when they have the same amount?

+4

Answers (1)

Know the Answer?

Oliver Richard · Answer 1

Volume of first pool - V1 (t) = 1285 + 32.75t

Volume of 2nd pool - V2 (t) = 1600 + 22.25t

Find t when V1 = V2

Equating we get - 1285 + 32.75t = 1600 + 22.25t

Solving for t we get 87.14 minutes

To find the Volume just substitute this value of t in one of the equations