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31 January, 20:06

Which of the following quartic functions has x=-1 and x=-2 as its only two real zeros?

x^4-3x^3+3x^2-3x+2

x^4+3x^3+3x^2-3x-2

x^4+3x^3+3x^2+3x+2

x^4-3x^3-3x^2+3x+2

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  1. 31 January, 22:55
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    x^4 - 3x^3 + 3x^2 - 3x + 2

    x = 1 and x = 2

    x^4 + 3x^3 + 3x^2 - 3x - 2

    x = - 0.5147 and x = 0.8516

    x^4 + 3x^3 + 3x^2 + 3x + 2 so this function is the answer

    x = - 2 and x = - 1

    x^4 - 3x^3 - 3x^2 + 3x + 2

    x = - 1 x = 1
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