Ask Question
1 February, 21:17

Not including myself and 1, my factors are 2, 3, 4, 6, 8, 12, 16, 24, 32, and 48. What number am I?

+2
Answers (2)
  1. 1 February, 23:05
    0
    2=2

    3=3

    4=2*2

    6=2*3

    8=2*2*2

    12=2*2*3

    16=2*2*2*2

    24=2*2*2*3

    32=2*2*2*2*2

    48=2*2*2*2*3

    This is called the prime factors of these numbers. As you can see 3 only appears once for a single number. The maximum number of 2s is 5.

    Thus the solution is 2*2*2*2*2*3=96
  2. 1 February, 23:14
    0
    2=2

    3=3

    4=2*2

    6=2*3

    8=2*2*2

    12=2*2*3

    16=2*2*2*2

    24=2*2*2*3

    32=2*2*2*2*2

    48=2*2*2*2*3
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Not including myself and 1, my factors are 2, 3, 4, 6, 8, 12, 16, 24, 32, and 48. What number am I? ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers