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16 May, 01:59

Find all solutions in the interval [0,2pi)

sec^2x + 2tanx = 3

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Answers (1)
  1. 16 May, 03:01
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    Tan^2x + 1 + tanx - 3 = 0 tan^2x + tanx - 2 = 0 (tanx + 2) (tanx - 1) = 0 tanx = - 2 or tanx = 1 x = 2.034 radians or x = 5.176 radians or x = pi/4 radians or x = 5pi/4 radians
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