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21 January, 23:36

Find all the values of x (where 0 < or equal to x and x < pi/2) in terms of pi for which cos (6x) = 0

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  1. 22 January, 01:09
    0
    cos (6x) = 0

    cos⁻¹[cos (6x) ] = cos⁻¹ (0)

    6x = 90

    6 6

    x = 15°

    x = ¹/₁₂π radians

    cos (6x) = 0

    cos⁻¹[cos (6x) ] = cos⁻¹ (0)

    6x = 270

    6 6

    x = 45

    x = ¹/₄π radians

    cos (6x) = 0

    cos⁻¹[cos (6x) ] = cos⁻¹ (0)

    6x = 450

    6 6

    x = 75

    x = ⁵/₁₂π radians
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