The ticket prices for a concert series were $12, $37, $45, $18, $8, $25, and $18. What was the ticket price of the eighth and final concert in this series if the set of 8 prices had a mean of $23, a mode of $18, and a median of $19.50?

Question

Mathematics

Hassan Carter

12 September, 14:19

The ticket prices for a concert series were $12, $37, $45, $18, $8, $25, and $18. What was the ticket price of the eighth and final concert in this series if the set of 8 prices had a mean of $23, a mode of $18, and a median of $19.50?

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Answers (1)

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Jaden Sloan · Answer 1

Given:

12, 37, 45, 18, 8, 25, 18,?

mean = 23

mode = 18

median = 19.50

using the mean

23 * 8 = 184

12 + 37 + 45 + 18 + 8 + 25 + 18 = 163

184 - 163 = 21

data set arranged in order from least to greatest:

8, 12, 18, 18, 21, 25, 37, 45

using the median

18 + 21 = 39

39 / 2 = 19.50

The missing ticket price is 21.